[Help] How To Code A 9-Day Rotation (Google Calendar Data Source?)

Watchface Design Expression Help
1

Some background: I am a firefighter and I want to make a watch face that will show which shift is currently working color coded for the given shift. It is a simple schedule/formula. (For someone…not me yet)

Example:
My shift (A shift) begins tomorrow and we can call that day 1. I will work days 1, 3, & 5…followed by 4 days off and the rotation resets. It’s a 9 day rotation with 3 shifts (A, B, & C).

My question is whether it would be possible to reference Google Calendar and have the corresponding shifts in there or if I need to find someone much smarter than me to develop a formula to show the correct shift/color?

Any advice would be tremendous. Thanks in advance for any tidbits!

Also, let me know if I’m being unclear and I will clarify with a graphical representation of my calendar.

2

My theory for this could be something like this:
Since it’s a simple 9 day rotation, building a formula that changes a color and letter on the watch face every 24 hours at 7:00AM (the start time for our shift).

Obviously, I have no idea where to even start, but I’m roughly envisioning something like this:

630D29CC-9EC0-4061-9706-F3995A19061E.jpeg1014×1015 324 KB

Not that exactly, but it somewhat gives a graphical represetation of what a “C Shift” day would look like.

3

Unfortunately, Facer doesn’t have access to google calendar.

The closest thing might be the newest collection of changeable complications, but I’m not sure if one of them is a google calendar thing (it needs an Android Wear 2.0 watch and I don’t have one).

4

Looks like you need to use Day in Year (#DD#) modulo 9.

Facer doesn’t support modulo (%), but you can hack it with the floor function.

Depending on the day of your rotation, in Facer Creator,
set transparency for the corresponding graphics as:

$(((#DD#/9)-floor(#DD#/9))*9)==2?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==3?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==4?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==5?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==6?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==7?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==8?100:0$
$(((#DD#/9)-floor(#DD#/9))*9)==0?100:0$```
5

@mrforman lemme know if you get this working… I need something like this to rotate around and show the current day of the week based on 7 positions

6

@HellionTRD Day of Week Rotational Code: (#DWR#-102)

7

I used ((#DOW#/7)*360) and it seems to be working, I did have to rotate the image so Sunday starts on the top

8

yes is working too… :slight_smile:

9

(((#DOW#+6)/7)*360)

To change week start (back 1).