Cooking with gas:
Haven’t quite worked it out yet. Been a bit distracted again with unneeded but understandably neccessary post councilling and so on but I have the brackets wrong myself so have a consistant but wrong answer for feels like using the previous: https://www.meteoswiss.admin.ch/weather/weather-and-climate-from-a-to-z/wind-chill.html
will look at that anew tomorrow. Nit sure why I could not see it in the tag list. Cheers
this works for apparent temperature in metric units (round(#WCT#+0.33*#WCHN#/100*6.105*exp(17.27*#WCT#/(237.7+#WCT#))-0.7*#WND#-4)) or
(round(#WCT#+0.0201465*#WCHN#*exp(17.27*#WCT#/(237.7+#WCT#))-0.7*#WND#-4))
And this one seems to work for imperial units setting
(round((((#WCT#-32)*5/9)+0.0201465*#WCHN#*exp(17.27*((#WCT#-32)*5/9)/(237.7+((#WCT#-32)*5/9)))-0.7*#WND#*1.6/3.6-4)*9/5)+32)
@petruuccios Thanks - it works perfectly!
My only problem is how you got to the above from the original formula - could you please give me the original formula so that I can try and see how you got from one to the other?
Thanks again.
It comes from the calculator page I suggested earlier, it is also on wikipedia.
it was the water vapour pressure formula and using exp in the tag that fooled me!
thanks again
Do not forget to add formulas for both unit systems and alternate them using #UNITSYS# tag, if you plan on publishing it, or there will be nonsensical results.
Yes indeed - there will be imperial and metric choices. I do intend to publish 
So.
(round(6+0.33*70/100*6.105*exp(17.27*6/(237.7+6))-0.7*122.3-4))Gosh . Dedicated Testing .
There was no way I was gonna miss my first chance to deliberately be out in a 75+mph gale. The gust were pretty exhilarating but after 10 minutes I feared not having the ability to hold onto my phone in sub zero (but not -81) chill.
Las time was accidental during hurricane Bawbag and it was only 45mph horizontal hale that time.
I was going to say I am not that stubborn but I now have some extreme raw numbers to plug in and I don’t trust the exp() function in Facer because it relies on interpretations of a constant so if the formula calls for x^y I’ll try again for x**y
I am thinking that if we go back to **0.16 we will be goodbut I have beeen awake for 70 hours now and the caffiene is failing but I don’t think today’s windchill was -81°
I think the idea is to work with the links we have (with or without humidity) and know that in Facer 2**3=8 (2^3) and 50**0.16*=1.86997241771 Google Calc
