I’m trying to make a dial that reveals the previous and following day number for the week #DdL# please can I request the code to do this: example when watch display 20 day, I need to be able to show the 19 and 21, thanks in advance
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Do you want a text based code or a rotating one (hand)?
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Hi Mellin, thanks for responding, a text based one based on #DdL#
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Ok, a text based one.
I can tell you right now that there is no way to create a fully working one for -1 day, there will be at least 1 day in every 3 days on which it will show the wrong number - 1st of March of any Leap year.
The +1 day should be no problem.
Give some time to think about it.
Edit- Scratch that, there is a way to overcome that problem, but it’s gone take a few text elements showing up and hiding.
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What i’m trying to do is create what looks like a rotating dial without actually making one, just want the numbers above and below the DAY number to be before and after, got any ideas?
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Next one (+1) is gone be easy so I will start with that one:
$(#Dd#+1)>#DIM#?1:(#Dd#+1)$
Check and let me know if it works.
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Yes, brilliant worked perfectly, thanks
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The -1 gone take some thinking (since there is no tag that gives back number of the day in the previous month).
I will be giving first text and then transparency code for it.
first element:
$(#Dd#-1)=0?0:#Dd#$
$(#Dd#-1)=0?0:100$
2:
$(#Dd#-1)=0&&#DM#=1||#DM#=2?31:0$
$(#Dd#-1)=0&&#DM#=1||#DM#=2?100:0$
3:
$(#Dd#-1)=0&&#DM#=4||#DM#=6?31:0$
$(#Dd#-1)=0&&#DM#=4||#DM#=6?100:0$
4:
$(#Dd#-1)=0&&#DM#=8||#DM#=9?31:0$
$(#Dd#-1)=0&&#DM#=8||#DM#=9?100:0$
5:
$(#Dd#-1)=0&&#DM#=11?31:0$
$(#Dd#-1)=0&&#DM#=11?100:0$
6 (end of February for a Leap year)
$(#Dd#-1)=0&&#DM#=3&&#DD#=61?29:0$
$(#Dd#-1)=0&&#DM#=3&&#DD#=61?100:0$
7 (end of February for a non Leap year):
$(#Dd#-1)=0&&#DM#=3&&#DD#=60?28:0$
$(#Dd#-1)=0&&#DM#=3&&#DD#=60?100:0$
8:
$(#Dd#-1)=0&&#DM#=5||#DM#=7?30:0$
$(#Dd#-1)=0&&#DM#=5||#DM#=7?100:0$
9:
$(#Dd#-1)=0&&#DM#=12||#DM#=10?30:0$
$(#Dd#-1)=0&&#DM#=12||#DM#=10?100:0$
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Wow, that’s amazing, I really hadn’t thought it through. You have a quick mind, I was just thinking of having the day before when the current day is the 1st showing as blank.
Does your code allow for all eventualities and if so do I execute as follows:
If I understand it, I need to create 9 layers for the day before location and then add your code to the text and transparency code respectively can you confirm that’s right please?
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That would be yes and yes.
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Again, thank you znakomity!!!
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Hi Mellin, put in the code and it’s not working it shows the same day?. Also noticed you used Dd, I also tried DdL for a leading zero
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maybe just the previous day to be zero transparency when current day is 1, but also can the previous and next have leading zero?
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Sorry, my bad.
First element should have:
$(#Dd#-1)=0?0:(#Dd#-1)$
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Hi Mellin, that worked perfectly. Also forget the question about leading zero I’ll run it with the #Dd# it actually looks better.
Thank you
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Hi Mellin, there seems to be a problem with February see screen grab. Just want to check when you sat first element should be you are referring to first layer is that correct?
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When you select day between 2 and the end of a month it should always give back (#Dd#-1).
Am I understanding it correctly that for some reason there is also a 31 showing up?
Can you check which one?
And I was refering to layer I mentioned as the first one for -1
From:
$(#Dd#-1)=0?0:#Dd#$
To:
$(#Dd#-1)=0?0:(#Dd#-1)$
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Hi, OK so the following months have this issue:
1st day of month is OK all other days have 31 in background
- Feb
- June
- July
- Sept
- Oct
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