I need to make the battery level appear in a meter with needle. Not a full circle gauge either. It would be more like the top gauges in this picture.

I’ve seen battery level meters on dials before, but can’t find any that allow me to inspect. This is going to be a great dial once I get it finished, but this is the last piece. Any help would be greatly appreciated!

Add a Dial element (hour, min, or sec). Then change the rotation for the battery level you want. For instance a full 360degree dial for Battery level would be: (#BLN#*3.6)

You can then add/subtract from this to set the start point (the above example starts at the top).

Also can create smaller dials like the version above where the rotation is only covering 60 degrees or so, the larger ones on the bottom look like 270 degrees.

I would suggest searching the forum a little more for examples. There are quite a few tutorials that explain in greater detail.

You need to know the starting angle, and the ending angle - typically for a speedometer style gauge (like the one you show), it will be either -120 or +240 degrees. Then measure how far you want the needle to rotate (Say 240 degrees - so that it will rotate from -120 degrees to +120 degrees from vertical).

Take that, and then use the expression builder with the battery PERCENT (I don’t use the integer) - and don’t forget your parenthesis around the formula:

(-120+((#BLP#/100)*240))

That basically means:
([THE START ANGLE]+([Batt % / 100]) * [The total angle you want the needle to move])

This will move the needle from LEFT (full) to RIGHT (Empty). - To reverse the direction, just invert the whole formula:

I’m new to all this and lucky.andrei and GAUSS have been extremely helpful, many thanks to them.
First off, I would like to know where to download Gauge Templates and Hands please, for Power Meters for both Watch and Phone?
Secondly, I have this image, which as I understand from above, has a starting point of 270 Degrees, and an end point of 90.

If that IS correct, then can someone please tell me where I’m going wrong when I try to implement the (270-((#BLP#/100)*90)) formula from above? I even tried (270-((#BLN#/100)*90))

The entire path the needle travels is -90 to +90 (or 270 to 450), so 180 degrees.
Also, #BLP# adds the percentage character, better use #BLN#.
It would be: (-90 + (#BLN#/100*180))
or (270 + (#BLN#/100*180))