Hi, i have problem. I want to build a rotational temperature dial but i can´t get it to run (my brain already hurts).
It should work in both celsius and Fahrenheit.
The celsius dial matches exactly in conversion to the fahrenheit one as shown in the middle.
I will change the displays automatically with $#WM#=F?100:0$ and $#WM#=C?100:0$.
Anyone a solution/formula ? All sort of help would be appreciated a lot.
Greetings, GAUSS.
Celsius:
Temperature range: 90 C
Angle range: 270 deg
Scale factor: 270 / 90 = 3 deg per 1 C
Uncorrected angle: (#WCT#*3)
Correction for minimum temp ( -40 C at -133.5deg ) : -133.5 - ( -40 x 3 ) = -13.5 deg
So, rotation: ((#WCT#*3)-13.5)
Test:
-40 C -> ( -40 x 3 ) - 13.5 = -133.5
0 C > ( 0 x 3 ) - 13.5 = -13.5
50 C -> ( 50 x 3 ) - 13.5 = 136.5
…
Fahrenheit:
Temperature range: 164
Angle range: 280 deg
Scale factor: 280 / 164 = 1.707 deg per 1F
So uncorrected angle: (#WCT#*1.707)
Correction for minimum temp ( -42 at -140deg ) : -140 - ( -42 x 1.707 ) = -68.3 deg
So, rotation: ((#WCT#*1.707)-68.3)
Test:
-42 F -> ( -42 x 1.707 ) - 68.3 = -140
40 F > ( 40 x 1.707 ) - 68.3 = 0
50 F -> ( 122 x 1.707 ) - 68.3 = 140
I hope that helps.
Great! Thanks for the help, i Will test today!
You are most welcome - I hope it works
As far as i can see it seems to work perfect! You made my day!
Cool!
Hi @GAUSS
I’m working on a watchface that includes almost same feature, half circle temperature gauge not full circle
Do you mind if I use the formulas provided by @mikeoday as well as the opacity formulas you used $#WM#=F?100:0$ and $#WM#=C?100:0$?
If you do I will remove the feature or find a different approach
For sure you can use his formula and mine as well.
BTW: That´s the watch face (in progress) matching to the temperature dial:
Working Title: GAUSS-Outdoor
That is wonderfully complex design! I like it!
Thank you @GAUSS & @mikeoday for your support
This is indeed a complex and very nicely detailed design… thumbs up
Thanks.
very good
You could try
$#WM#==F?(170-(clamp(#WCT#,32,104)*2.5)):(90-(clamp(#WCT#,0,30)*6))$
edit: Sorry the above expression has an error in the fahrenheit part, it should be
$#WM#==F?(196.66-(clamp(#WCT#,32,86)*3.333)):(90-(clamp(#WCT#,0,30)*6))$
hi, what a complex code! seems to be right on my face, I will test during the week, because the temperature is bad to test! I only use degrees C, at the moment thank you very much for your help, I’m from Curitiba Pr, Brazil
You are most welcome - hopefully it will work ok on your watch.
Hi Mikeoday! By abusing your good will, you can recalculate the temperature from 0 to 40 degrees, because the coloration from 0 to 30 was strange, as the movement was great!
I think this will work
$#WM#==F?(170-(clamp(#WCT#,32,104)*2.5)):(90-(clamp(#WCT#,0,40)*4.5))$muito bom, obrigado novamente, nota 10