Problem: temperature C/F rotational

GAUSS · September 9, 2019, 8:50pm

Thanks.

marcosrubian · October 30, 2019, 7:28pm

very good

marcosrubian · October 30, 2019, 8:23pm

hi i need some help, i am seriously not good at math, as would be the tag for this look, help

mikeoday · October 31, 2019, 4:55am

You could try

$#WM#==F?(170-(clamp(#WCT#,32,104)*2.5)):(90-(clamp(#WCT#,0,30)*6))$

edit: Sorry the above expression has an error in the fahrenheit part, it should be

$#WM#==F?(196.66-(clamp(#WCT#,32,86)*3.333)):(90-(clamp(#WCT#,0,30)*6))$

marcosrubian · October 31, 2019, 5:41am

teste
hi, what a complex code! seems to be right on my face, I will test during the week, because the temperature is bad to test! I only use degrees C, at the moment thank you very much for your help, I’m from Curitiba Pr, Brazil

mikeoday · October 31, 2019, 8:28am

You are most welcome - hopefully it will work ok on your watch.

marcosrubian · November 1, 2019, 4:20am

Hi Mikeoday! By abusing your good will, you can recalculate the temperature from 0 to 40 degrees, because the coloration from 0 to 30 was strange, as the movement was great!

mikeoday · November 1, 2019, 7:23am

I think this will work

$#WM#==F?(170-(clamp(#WCT#,32,104)*2.5)):(90-(clamp(#WCT#,0,40)*4.5))$

marcosrubian · November 1, 2019, 7:48am

muito bom, obrigado novamente, nota 10

marcosrubian · November 1, 2019, 7:48am

very good, thanks again, note 10

oregon900 · November 1, 2019, 11:14am

Hi guys, I also take advantage, as on other occasions, to use your advice and formulas, thanks.

marcosrubian · November 2, 2019, 2:44am

hi mikeoday, it really just got better now! Is the math from 0 to 40 correct? If you don’t mind and have time without commitment, could you reveal how this math is done? because just looking can not understand how it does! would you like me to somehow repay this help?

mikeoday · November 2, 2019, 4:44am

Well I think it is right. I walk you through it and that should confirm ( or otherwise )

$#WM#==F?(170-(clamp(#WCT#,32,104)*2.5)):(90-(clamp(#WCT#,0,40)*4.5))$

If the watch/phone weather units are imperial ( ie. #WM#==F ) then the expression is

(170-(clamp(#WCT#,32,104)*2.5))

check:
#WCT# == 32 ( equivalent to 0C )
clamp(32,32,104) will return 32
32*2.5 = 80
170-80 = 90
So, when temp = 32, rotation = 90 degrees

#WCT# == 104 ( equivalent to 40C )
clamp(104,32,104) will return 104
104*2.5 = 260
170-260 = -90
So, when temp = 104, rotation = -90 degrees

If the watch/phone weather units are metric( ie. #WM# not = F ) then the expression is

(90-(clamp(#WCT#,0,40)*4.5))

check:
#WCT# == 0 ( equivalent to 32F )
clamp(0,0,40) will return 0
0*4.5 = 0
90-0 = 90
So, when temp = 0, rotation = 90 degrees

#WCT# == 40 ( equivalent to 104F )
clamp(40,0,40) will return 40
40*4.5 = 180
90-180 = -90
So, when temp = 40, rotation = -90 degrees

I hope that helps.

marcosrubian · November 2, 2019, 5:01am

very good! now I understand! super explanation, all right here, as soon as I finish revealing how it was and put your credits to the face, I’m very grateful for your help!

mikeoday · November 2, 2019, 6:27am

You are most welcome.

marcosrubian · November 14, 2019, 5:37am

Hi! Do you know how to use these tags for Cº and Fº at the same time? I am using it in degrees Cº I would like it to work in both modes
$ # WCT # <= 10? 100: 0 $
$ # WCT # <= 19 && # WCT #> = 11? 100: 0 $
$ # WCT # <= 25 && # WCT #> = 20? 100: 0 $
$ # WCT # <= 30 && # WCT #> = 26? 100: 0 $
$ # WCT #> = 31? 100: 0 $

mikeoday · November 14, 2019, 8:12am

No the results will be different for Celsius and Fahrenheit

You can use the following tag to test for which units are active on the user’s watch:

marcosrubian · November 14, 2019, 4:33pm

thanks

akar.zaephyr · June 17, 2021, 10:44am

I know this is an old thread by your maths, @mikeoday, helped me greatly so I would like to extend my thanks as well!

mikeoday · June 17, 2021, 12:28pm

Thanks, are most welcome and I’m glad it helped!